Show_If not working with a Virtual Column

I have a virtual column that concatenates with a column

If that column is empty I do not want to show the virtual column

I use a Show_If statement within the virtual column

However, it shows every time whether the column has data or not

3X_1_e_1e76e7f65242cc640c87849ef4a9e8948d26adea.png

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3X_3_b_3bd04e2c81eab553635e72f6cbb7c5eda6675a0e.png

I use the same code in both the actual column and the virtual column and it works for the actual column

ISNOTBLANK([Banned from])

Any assistance would be appreciated

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Steve
Platinum 4
Platinum 4

Please post a screenshot of the configuration screen for the column that produces this line:

3X_a_5_a5809e7f7b8810fcaa3471fa9bd6bac8081169b2.png

Hope this is what you want

Steve, the problem is that you concentrate will never be blank as it will always contain โ€œBanned fromโ€. You need to either test for the column to be equal to โ€œBanned fromโ€ or even better change the virtual column to be IF(ISBLANK([Banned From]),"",CONCATENATE("Banned from ",[Banned from])). This will leave the vc blank if [Banned from] is blank and hence will not show.

Hi Thank you for taking the time to reply. I put your code in the Formula and it works brilliantly.
However, I still do not really understand why the Show_If didnโ€™t work.
Surely putting ISNOTBLANK([Banned From]) in the Virtual Column should only show IF [Banned From] contains data!

But thanks anyway!

Show_If does not affect the display of header columns in a detail view. I consider this a bug.

Attn @Arthur_Rallu

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