Hello,
Can anyone help me get the right expression, please?
I applied one of my column types as
" EnumList" to get multiple selections.One of my selection is
" Other".
If I select " Other", I want to allow users to specify what is other. Thatโs why I created another column as " If other" by giving text function. So, I used Show If valdiation like =[column name]=โOtherโ.
It doesnโt work. It is showing an error like
Cannot compare List with Text in ([column name] = โOtherโ).
Hi @Kyaw_Za, I request you to try
IN(โOtherโ, [EnumListColumnName]) in Show_if
Thank you for your help
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