Hi everyone,
I am creating a desktop style page that links people to certain views. Based around this video.
I want to create the page so it can either link directly to a view or link to a URL. The below is the formula I have which i believe should be correct but it is giving me this error.
IF function is used incorrectly:the second input (if-result) and third input(else-result) should have the same type.
IF([type]=โURLโ, LINKURL([URL]), LINKTOVIEW([Option 2]) )
Anyone know how to get around this?
You are mixing data types- you can do it with two different columns and show_ifs.
Sorry Bellave, Im not following. I need the action to change depending on the whats in the data?
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