SUM, MAX of many date columns per row to find latest timestamp

Hi guys.

I have an “Orders” table that has 9 columns that track a changetimestamp on the [Progress] and I am wanting to give the user the ability to: order by the most recently updated progress. So in a VC i am looking at:
MAX([Creation Date Stamp],[Quote Sent Date],[Deposit Paid Date],[…])
and then wrap this in a SUM(MAX()TODAY+1) to give a final result of:

[Order Number] [Last Progress Update]
[1] |4 days ago|
|2| |5 days ago|
|3| |8 days ago|
|4| |17 days ago|
|5| |28 days ago|

If that makes sense? I am struggling with the MAXROW expression

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Thank you @Steve_Chambers . Good to know it basically works.

You are correct. please wrap the result by HOUR()

Maybe something like

HOUR((TODAY()- MAX(
LIST(
DATE([Creation Date Stamp]) ,
DATE([Quote Sent Date]) ,
DATE([Deposit Paid Date]) ,
DATE([Confirmation Sent Date]) ,
DATE([Production Start Date]) ,
DATE([Production End Date]) ,
DATE([Invoice Sent Date]) ,
DATE([Invoice Paid Date]) ,
DATE([Follow-up Letter Sent Date])
)))) / 24

Please refer the first duration expression example in the article below under the section " Examples that Compute Durations in Days, Months, or Years"

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6 REPLIES 6

If I have understood your requirement correctly, could you try in the VC of [Last Progress Update]

CONCATENATE( (TODAY()- MAX(DATE([Creation Date Stamp]) , [Quote Sent Date],[Deposit Paid Date],[…])), " days ago")

I can’t get past the ‘MAX function used incorrectly’

I think you have understood me correctly, to clarify i have 9 columns in my Orders table that house datetime values, i would like to build a VC that finds that latest (MAX) datetime for each row

then wrap it in concat((today - max(date()))
Its just the max date i’m struggling with

Please try

CONCATENATE( (TODAY()- MAX(
LIST(DATE([Creation Date Stamp]) , DATE([Quote Sent Date]),DATE([Deposit Paid Date]), DATE([…]))), " days ago")

Thanks
your formula is working!
However it’s displaying as a duration, its outputting the result in hhh:mm:ss ie 72:00:00

I think i need to convert a DateTime value to a Time value with TIME() , then subtract a zero time to convert a Time value to a Duration value: HOUR(TIME(NOW()) - "00:00:00") as per HOUR() expression

I had a second VC working for a brief second until i realized the original VC with the below formula was changed to decimal, which broke the app

I need to divide the duration by 24 somehow i think, here’s the working formula to output hours since MAX

(TODAY()- MAX(
LIST(
DATE([Creation Date Stamp]) ,
DATE([Quote Sent Date]) ,
DATE([Deposit Paid Date]) ,
DATE([Confirmation Sent Date]) ,
DATE([Production Start Date]) ,
DATE([Production End Date]) ,
DATE([Invoice Sent Date]) ,
DATE([Invoice Paid Date]) ,
DATE([Follow-up Letter Sent Date])
)))

to get that to days since max, something like this maybe?

HOUR(NOW() - (DATETIME(TODAY()) - [Last Updated]) )/24 ??

Thank you @Steve_Chambers . Good to know it basically works.

You are correct. please wrap the result by HOUR()

Maybe something like

HOUR((TODAY()- MAX(
LIST(
DATE([Creation Date Stamp]) ,
DATE([Quote Sent Date]) ,
DATE([Deposit Paid Date]) ,
DATE([Confirmation Sent Date]) ,
DATE([Production Start Date]) ,
DATE([Production End Date]) ,
DATE([Invoice Sent Date]) ,
DATE([Invoice Paid Date]) ,
DATE([Follow-up Letter Sent Date])
)))) / 24

Please refer the first duration expression example in the article below under the section " Examples that Compute Durations in Days, Months, or Years"

oh no you’ve gone and done it now, i’ll never leave you alone

thanks for the link, i’ll dive in soon the scheduling system is the next view i will build

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