Count the instances of "Yes" (in a row) across 5 specific columns

Evening,

Please could someone show me where Iโ€™m going wrong with this?

Iโ€™m trying to count the instances of โ€œYesโ€ (in a row) across 5 specific columns.

I have the following in VC but Iโ€™m not getting the right result.

COUNT(SELECT(survey[branch_A_decision], [THISROW].[branch_A_decision] = โ€œYesโ€))+
COUNT(SELECT(survey[branch_B_decision],[_THISROW].[branch_B_decision] = โ€œYesโ€))+
COUNT(SELECT(survey[branch_C_decision],[_THISROW].[branch_C_decision] = โ€œYesโ€))+
COUNT(SELECT(survey[branch_D_decision],[_THISROW].[branch_D_decision] = โ€œYesโ€))+
COUNT(SELECT(survey[branch_E_decision],[_THISROW].[branch_E_decision] = โ€œYesโ€))

I had a look at the posts below but couldnโ€™t convert them.

Thanks in advanceโ€ฆ

Solved Solved
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1 ACCEPTED SOLUTION

Steve
Platinum 4
Platinum 4

Try:

(
  IFS(([branch_A_decision] = "Yes"), 1),
  + IFS(([branch_B_decision] = "Yes"), 1),
  + IFS(([branch_C_decision] = "Yes"), 1),
  + IFS(([branch_D_decision] = "Yes"), 1),
  + IFS(([branch_E_decision] = "Yes"), 1)
)

View solution in original post

3 REPLIES 3

Steve
Platinum 4
Platinum 4

Try:

(
  IFS(([branch_A_decision] = "Yes"), 1),
  + IFS(([branch_B_decision] = "Yes"), 1),
  + IFS(([branch_C_decision] = "Yes"), 1),
  + IFS(([branch_D_decision] = "Yes"), 1),
  + IFS(([branch_E_decision] = "Yes"), 1)
)

Hi @Steve,

That works! Thank you very much!

I love IFS()โ€ฆ โ€ฆ it makes formulas so clean.

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