How can I download an image from an application to my phone?
Solved! Go to Solution.
Then I reckon you somehow solve the problem?
You can do that either with the printscreen or sending it with an Workflow/email.
I plan to add a lot of image from the smartphone’s gallery as well as downloading images to a smartphone, so it’s very inconvenient to send emails every time I download, is there another solution to my problem, including downloading offline files without access to the Internet?
You create virtual column to dynamically generate the hyperlink to the saved image file. When your user click the link app will open up image in browser . User hold down over the image and then download to device become available to save the file to local .
Good workaround!
thanks for the help
Thank you
You are welcome
Perhaps you know an example of a proposal that implements this solution could share with me
I dont have particular sample for this, but you just create virtual column with expression like this.
hyperlink(CONCATENATE(“https://www.appsheet.com/template/gettablefileurl?appName=”, ENCODEURL(“YOURAPPNAME-APPID”), “&tableName=”, ENCODEURL(“YOURTABLENAME”), “&fileName=”, ENCODEURL([YOURIMAGEDATAFIELD])),“Link to image”)
This should generate hyperlink to your image file on the same row. Click hyperlink on your mobile phone then it will open external browser. Keep pressing down your thumb on the image, then option should become available to download image.
Thank you very much. I’ll do it now.
Make sure to set the data type to URL for that virtual column.
Should be easy one.
Ok
I changed to the formula correctly?
hyperlink(CONCATENATE(“https://www.appsheet.com/template/gettablefileurl?appName=Фотоконкурс-1044910”, ENCODEURL(“YOURAPPNAME-APPID”), “&tableName=Лист1”, ENCODEURL(“в/у первая сторона”), “&fileName=”, ENCODEURL([в/у первая сторона])),“Link to image”)
can i click on the image i and holding select using the download menu?
Tell me
I can construct the expression for you.
One minute
1 Фотоконкурс-1044910
2 Лист1
3 в/у первая сторона
Could you try this one instead?
hyperlink(CONCATENATE(“https://www.appsheet.com/template/gettablefileurl?appName=”, ENCODEURL(“Фотоконкурс-1044910”), “&tableName=”, ENCODEURL(“Лист1”), “&fileName=”, ENCODEURL([в/у первая сторона])),“Link to image”)
ok
Should work.
Hi @Koichi_Tsuji i face same problem and tried to reconstruct the link, here are my code
hyperlink(CONCATENATE(“https://www.appsheet.com/template/gettablefileurl?appName=”, ENCODEURL(“AssetOpname-office365-2147180”), “&tableName=”, ENCODEURL(“ASSET”), “&fileName=”, ENCODEURL([Photo full])),“Link to image”)
but the image not shown
Thanks a lot, everything works. The link opens in an external browser.
Perfect.
Press down with thumb or any other finger on the image. Not sure you are on I phone or android, but download option should become available after few secs.
What do they say? Sorry, I need a translator!
Open in a new tab, download the image on
Then I reckon you somehow solve the problem?
Yes, you helped me a lot
Great to hear.
Now case is closed, off course, it could not be a perfect solution with you though.
Hello, I created three additional fields with hyperlinks in the image. Is it possible to avoid creating these additional fields so that the hyperlink opens in an external browser when you click on the image?
Other community member may have workaround, I dont have any idea to achieve it.
But hitting hyperlink to open the image in browser should be good enough, and do the same thing by hitting the file in browser technically.
Also i dont want to have app to open image in external browser by hitting image, as it could happen we hit the image unintentionally by swiping finter on the app over the image.
Altenative could be set the card views for all the image files you have. Then create action open image url in external broswer. And associate such actoin to card view “on click”
Find this image on Google
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Just throwing this out there… There is an action to download a file…
You could also create a Virtual Column type file and wrap the image column in TEXT() or CONCATENATE() and then leverage that in the open file action… (Pretty much works the same as your URL)
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