I have 2 tables.
in the first table, in the field โCittaSLโ, I would take the values from another table in the column โComuneโ. I have solved this with type โRefโ.
Now when I take a value from โCittaSLโ, I would take the corresponding value also for other 2 fields in the second table โProvinciaSLโ.
I have tried with these formulas but not works:
IN( [_THIS], SELECT(GA_ANA_Comuni[PV], [_THISROW].[CittaSL] = [Comune]))
ANY(SELECT(GA_ANA_Comuni[PV], ([Comune] = [_THIS].[CittaSL])))
SELECT(GA_ANA_Comuni[PV],[Comune]=[_THISROW].[CittaSL])
Solved! Go to Solution.
Hi @Marc_Dillon,
thanks for your reply.
It works, but the field that is dinamically called, appears only when is chosen from the dropdown. It is possible to see it anyway also when it is not called?
Iโm not sure what youโre asking there. Can you elaborate?
The 2 fields that I call dinamically with the dropdown are hidden in the form if I not choose any value in the dropdown โCittaSLโ.
It is possible to see them anyway and so empty when I donโt choose nothing in the dropdown โCittaSLโ?
@Marc_Dillon
If you donโt choose anything for โCittaSLโ, the other 2 fields will be empty.
You can try to enter the expression TRUE
into those 2 fieldsโ show_if, but Iโm not 100% sure thatโll work.
Why do you need them to be visible?
If you donโt choose anything for โCittaSLโ, the other 2 fields will be empty.
Yes but I would these 2 fields always visibleโฆ
Where I have to put the expression TRUE?
Do you mean this?
Yes
not worksโฆ
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