Subtract lists to produce another containing only the unique items of the first list that aren't also in the second

I don’t know anymore what formula to use to get this to work. What I want is from a list() group - the list() column will return the remainder of the right-hand side list.

it doesn’t work like this photo I’m showing,

can someone help me???

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13 REPLIES 13

Steve
Platinum 4
Platinum 4

Original post:

Steve
Platinum 4
Platinum 4

For reference:

Steve
Platinum 4
Platinum 4

Please post a screenshot of the complete expression you’re using.

Please advise

Have you used Test to confirm your expression produces the expected results?

3X_0_3_037c0e8b2b563e298c2f578b33de5fed839fe5c9.png

3X_2_7_27bf1eab5849edd6bcaee0816e6fca9314ced691.png

Yes, I have used test…
but the results are not as expected.

for with one item, like screenshot “Jan” can work, but with reduction Jan,Feb,Mar

Reduction doesn’t work

Wrap your SELECT() expression with CONCATENATE() and SPLIT():

SPLIT(CONCATENATE(SELECT(...)), " , ")

See also:

it works @Steve
thank you,

I had thought about using split, but was confused about how to combine it.

Could you check this anyway? Just to make sure we are not fixing a problem made initialy by changing the Item separator so that others could avoid it in the future

like this

Thanks.
Seems like Item separator is "," instead of " , "

Please post your [Pembayaran Bulan] config.
Like this:

Seems like you were playing with the Item separator. By default it is " , ". Leave it as default

Good point!

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